Hydrocarbons Question 230
Question: An optically active alkyl bromide X ( $ C_6H _{13}Br $ ) upon treatment with ethanolic KOH solution forms two alkenes Y and Z with their molecular formula ( $ C_6H _{12} $ ). Y and Z are positional isomers. Z upon treatment with cold, dilute alkaline $ KMnO_4 $ solution gives a meso-diol. Hence, X is
Options:
A) 2-bromohexane
B) 1-bromo-2, 3-dimethyl butane
C) 3-bromohexane
D) 2-bromo-2, 3-dimethyl butane
Show Answer
Answer:
Correct Answer: C
Solution:
[c] For meso diol, alkene must be cis symmetrical 3-hexene.
BETA
