Hydrocarbons Question 24
Question: Ethene when treated with $ Br_2 $ in the presence of $ CCl_4 $ which compound is formed [RPMT 1997; DCE 2001; KCET (Med.) 1999]
Options:
A) 1, 2-dibromoethane
B) 1-bromo-2-chloroethane
C) Both A and B
D) 1, 1, 1-tribromoethane
Show Answer
Answer:
Correct Answer: A
Solution:
$ CH_2=CH_2+Br_2\xrightarrow{CCl_4}\underset{\begin{smallmatrix} \text{1, 2-dibromo } \\ ethane \end{smallmatrix}}{\mathop{\underset{Br}{\mathop{\underset{|}{\mathop{CH_2}}}}-\underset{\underset{Br}{\mathop{|}}}{\mathop{CH_2}}}} $
BETA
