Hydrocarbons Question 243
Question: $ CH_3-\overset{CH_3}{\mathop{\overset{|}{\mathop{CH}}}}C\equiv CH~\xrightarrow{excessHBr} $ The product of the above reaction is:
Options:
A) $ CH_3-\overset{CH_3}{\mathop{\overset{|}{\mathop{CH}}}}-\overset{Br}{\mathop{\overset{|}{\mathop{C}}}}={{\overset{Br}{\mathop{\overset{|}{\mathop{CH}}}}}_2} $
B) $ CH_3-\overset{CH_3}{\mathop{\overset{|}{\mathop{CH}}}}-\overset{Br}{\mathop{\overset{|}{\mathop{C}}}}=CH_2 $
C) $ CH_3-\overset{CH_3}{\mathop{\overset{|}{\mathop{CH}}}}-\underset{Br}{\mathop{\underset{|}{\mathop{\overset{Br}{\mathop{\overset{|}{\mathop{C}}}}}}}}=CH_3 $
D) $ CH_3-\overset{CH_3}{\mathop{\overset{|}{\mathop{CH}}}}-CH_2-\underset{Br}{\mathop{\underset{|}{\mathop{\overset{Br}{\mathop{\overset{|}{\mathop{CH}}}}}}}} $
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Answer:
Correct Answer: C
Solution:
[c] $ CH_3-\overset{CH_3}{\mathop{\overset{|}{\mathop{CH}}}}-\underset{Br}{\mathop{\underset{|}{\mathop{\overset{Br}{\mathop{\overset{|}{\mathop{C}}}}}}}}=CH_3 $
BETA
