Hydrocarbons Question 258
Question: $ HOCl $ reacts on 3-methyl-2-pentene, the main product will be:
Options:
A) $ CH_3-CH=\underset{Cl}{\mathop{\underset{|}{\mathop{C}}}}-CH-(OH)-CH_3 $
B) $ CH_3-\overset{OH}{\mathop{\overset{|}{\mathop{C}}}}H-\overset{CH_3}{\mathop{\overset{|}{\mathop{\underset{Cl}{\mathop{\underset{|}{\mathop{C}}}}}}}}-CH_2-CH_3 $
C) $ CH_3-\overset{Cl}{\mathop{\overset{|}{\mathop{C}}}}H-\overset{CH_3}{\mathop{\overset{|}{\mathop{\underset{OH}{\mathop{\underset{|}{\mathop{C}}}}}}}}-CH_2-CH_3 $
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
[c] The reaction follows Markownikoff rule $ \underset{3-Methyl-2-pentene}{\mathop{CH_3CH_2-\overset{CH_3}{\mathop{\overset{|}{\mathop{C}}}}=\overset{H}{\mathop{\overset{|}{\mathop{C}}}}-CH_3+\overset{\delta -}{\mathop{HO}}\overset{\delta +}{\mathop{Cl}}}}\xrightarrow{{}}CH_3CH_2-\underset{OH}{\mathop{\overset{CH_3}{\mathop{\underset{|}{\mathop{\overset{|}{\mathop{C}}}}}}}}-\underset{Cl}{\mathop{\overset{H}{\mathop{\underset{|}{\mathop{\overset{|}{\mathop{C}}}}}}}}-CH_3 $
BETA
