Hydrocarbons Question 268
Question: In a reaction, if half of the double bond is broken and two new bonds are formed, this is a case of [AMU 1983; NCERT 1978; CPMT 1983]
Options:
A) Elimination
B) Addition
C) Displacement
D) Rearrangement
Show Answer
Answer:
Correct Answer: B
Solution:
e.g.
$ CH_2=CH_2+Br_2\to \underset{\underset{Br}{\mathop{|}}\underset{Br}{\mathop{|}}}{\mathop{CH_2-CH_2}} $ Half of the double bond is broken.
It means $ \pi $ bond is broken while sigma bond is retained also two new $ C-Br $ bonds are formed.
BETA
