Hydrocarbons Question 271
Question: In reaction sequence $ CH_2=CH_2\xrightarrow[acid]{Hypochlorous}M\xrightarrow{R}\underset{CH_2OH}{\overset{CH_2OH}{\mathop{|}}} $ molecule ‘M’ and reagent ‘R’ respectively are
Options:
A) $ CH_3CH_2Cl $ and $ NaOH $
B) $ CH_3CH_2OH $ and $ H_2SO_4 $
C) $ CH_2(Cl)CH_2OH $ and aqueous $ NaHCO_3 $
D) and Heat
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Answer:
Correct Answer: C
Solution:
[c]
BETA
