Hydrocarbons Question 297

Question: What is the molecular formula of the alkane, the 5.6 litre of which weight 11 g at STP [MP PMT 2003]

Options:

A) $ C_6H _{14} $

B) $ C_2H_6 $

C) $ C_4H _{10} $

D) $ C_3H_8 $

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Answer:

Correct Answer: D

Solution:

Molecular mass can be obtained by the victor mayer process $ Molecularmass=\frac{Weight}{Vml.}\times 22400 $

$ =\frac{11}{5600}\times 22400=44 $