Hydrocarbons Question 297
Question: What is the molecular formula of the alkane, the 5.6 litre of which weight 11 g at STP [MP PMT 2003]
Options:
A) $ C_6H _{14} $
B) $ C_2H_6 $
C) $ C_4H _{10} $
D) $ C_3H_8 $
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Answer:
Correct Answer: D
Solution:
Molecular mass can be obtained by the victor mayer process $ Molecularmass=\frac{Weight}{Vml.}\times 22400 $
$ =\frac{11}{5600}\times 22400=44 $