A) Na
B) $ {Na}/{\text{liquid }NH_3}; $
C) $ {Na}/{\text{dry ether}}; $
D) $ {Na}/{\text{dry alcohol}}; $
Correct Answer: C
$ RCl+2Na+RCl\underset{Ether}{\mathop{\xrightarrow{Dry}}}2NaCl+\underset{Alkane}{\mathop{R-R}} $
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