Hydrocarbons Question 346
Question: A gas formed by the action of alcoholic KOH on ethyl iodide, decolorises alkaline $ KMnO_4 $ solution. The gas is [CPMT 1974, 91; MP PET 1985; IIT-JEE 1982]
Options:
A) $ CH_4 $
B) $ C_2H_6 $
C) $ C_2H_4 $
D) $ C_2H_2 $
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Answer:
Correct Answer: C
Solution:
$ CH_3CH_2I+KOH(alc)\to CH_2=CH_2+KI+H_2O $
$ CH_2=CH_2+\underset{\begin{matrix} \\ \begin{matrix} Alk\text{.Pink} \\ {} \\ \end{matrix} \\ \end{matrix}}{\mathop{KMnO_4}}\xrightarrow{H_2O}\underset{Colourless}{\mathop{\underset{OH}{\mathop{\underset{|}{\mathop{CH_2}}}}-\underset{OH}{\mathop{\underset{|}{\mathop{CH_2}}}}+MnO_2}} $
BETA
