A) $ C_2H_4 $
B) $ CH_3O $
C) $ CH_3Br $
D) $ CH_3CH_2OH $
Correct Answer: C
$ CH_3Br+H_2 $
$ \xrightarrow{LiAlH_4} $
$ CH_4 $ (methane) $ \xrightarrow{Na}CH_3-CH_3 $ (Ethane)
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