Hydrocarbons Question 361
Question: The compound formed by passing ethylene gas into cold alkaline solution of $ KMnO_4 $ is [NCERT 1974, 81; CPMT 1979, 86, 88; MP PET 1985, 95; AFMC 1998]
Options:
A) Ethyl alcohol
B) Acetaldehyde
C) Acetic acid
D) Ethylene glycol
Show Answer
Answer:
Correct Answer: D
Solution:
$ \underset{Ethene}{\mathop{CH_2=CH_2}}\xrightarrow{Cold\text{.alk}\text{.}KMnO_4}\underset{Ethyleneglycol}{\mathop{\underset{OH}{\mathop{\underset{|}{\mathop{CH_2}}}}-\underset{OH}{\mathop{\underset{|}{\mathop{CH_2}}}}}} $
BETA
