A) 1-butene
B) 2-butene
C) 1-butanol
D) 2-butanol
Correct Answer: A
$ ClCH_2-CH_2-CH_2-CH_3\xrightarrow{alc.KOH} $
$ \underset{1-butene}{\mathop{CH_2=CH-CH_2-CH_3}} $
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