Hydrocarbons Question 378
Question: At low temperatures, the slow addition of molecular bromine to $ CH_2=CH-CH_2-C\equiv CH $ gives [Roorkee Qualifying 1998]
Options:
A) $ CH_2=CH-CH_2-CBr=CHBr $
B) $ BrCH_2-CHBr-CH_2-C\equiv CH $
C) $ CH_2=CH-CH_2-CH_2-CBr_3 $
D) $ CH_3-CBr_2-CH_2-C\equiv CH $
Show Answer
Answer:
Correct Answer: A
Solution:
$ CH_2=CH-CH_2-C\equiv CH+Br_2\to $
$ CH_2=CH-CH_2-\underset{\underset{Br}{\mathop{|}}}{\mathop{C=}}\underset{\underset{Br}{\mathop{|}}}{\mathop{CH}} $
BETA
