Hydrocarbons Question 382
Question: Propene when heated with chlorine at about $ 500^{o}C $ forms [MP PET 1997]
Options:
A) $ CH_2Cl.CH=CH_2 $
B) $ CH_3.CHCl.CH_2Cl $
C) $ CH_2Cl.CHCl.CH_2Cl $
D) All the three
Show Answer
Answer:
Correct Answer: A
Solution:
$ CH_3-CH=CH_2+Cl_2\xrightarrow{500^{o}C} $
$ \underset{\underset{Cl}{\mathop{|}}}{\mathop{CH_2}}-CH=CH_2+HCl $ This reaction is called allylic halogenation reaction because halogenation occurs at the allylic position of an alkene
BETA
