Hydrocarbons Question 386
Question: Reaction of $ Br_2 $ on ethylene in presence of $ NaCl $ gives
Options:
A) $ BrCH_2-CH_2Br $
B) $ ClCH_2-CH_2Br $
C) Both A and B
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
$ CH_2=CH_2+Br_2\xrightarrow{NaCl}\underset{\text{1,2}-dibromoethane}{\mathop{\underset{\underset{Br}{\mathop{|}}}{\mathop{CH_2}}-\underset{\underset{Br}{\mathop{|}}}{\mathop{CH_2}}}} $
$ \underset{1-bromo-2-chloroethane}{\mathop{+\underset{\underset{Cl}{\mathop{|}}}{\overset{2}{\mathop{CH_2}}}-\underset{\underset{Br}{\mathop{|}}}{\overset{1}{\mathop{CH_2}}}}} $
BETA
