Hydrocarbons Question 40
Question: Propylene on hydrolysis with sulphuric acid forms [MH CET-2003]
Options:
A) n-propyl alcohol
B) Isopropyl alcohol
C) Ethyl alcohol
D) Butyl alcohol
Show Answer
Answer:
Correct Answer: B
Solution:
$ \underset{Propylene}{\mathop{CH_2=CH-CH_3+H_2O}}\xrightarrow{H_2So_4} $
$ \underset{\text{Isopropyl alcohol}}{\mathop{CH_3-\overset{OH}{\mathop{\overset{|}{\mathop{C}}H}}-CH_3}} $
Thus in this reaction isopropyl alcohol is formed.
BETA
