Hydrocarbons Question 41
Question: When ethyl iodide and propyl iodide react with Na in the presence of ether, they form [BHU 1997]
Options:
A) One alkane
B) Two alkanes
C) Four alkanes
D) Three alkanes
Show Answer
Answer:
Correct Answer: D
Solution:
$ C_2H_5I+2Na+C_3H_7I\underset{Ether}{\mathop{\xrightarrow{Dry}}} $
$ \underset{Pentane}{\mathop{C_2H_5-C_3H_7}}+2NaI $
$ C_2H_5I+2Na+C_2H_5I\underset{Ether}{\mathop{\xrightarrow{Dry}}}\underset{Butane}{\mathop{C_2H_5-C_2H_5}}+2NaI $
$ C_3H_7I+2Na+C_3H_7I\underset{Ether}{\mathop{\xrightarrow{Dry}}}\underset{Hexane}{\mathop{C_3H_7-C_3H_7}}+2NaI $
BETA
