Hydrocarbons Question 410
Question: When isobutyl magnesium bromide in dry ether is treated with absolute ethyl alcohol, the products formed are [IIT-JEE 1995]
Options:
A) $ \underset{CH_3}{\mathop{\underset{|}{\mathop{CH_3-CH-CH_2OH}}}} $ and $ CH_3CH_2MgBr $
B) $ \underset{CH_3}{\mathop{\underset{|}{\mathop{CH_3-CH-CH_2-CH_2-CH_3}}}} $ and $ Mg(OH)Br $
C) $ \underset{CH_3}{\mathop{\underset{|}{\mathop{CH_3-CH-CH_3}}}} $ and $ CH_3-CH_2OMgBr $
D) $ \underset{CH_3}{\mathop{\underset{|}{\mathop{CH_3-CH-CH_3}}}},CH_2=CH_2 $ and $ Mg(OH)Br $
Show Answer
Answer:
Correct Answer: C
Solution:
$ CH_3-\underset{\underset{CH_3}{\mathop{|}}}{\mathop{CH}}-CH_2-\xrightarrow{{}} $
$ \underset{Isobutane}{\mathop{CH_3-\underset{CH_3}{\mathop{\underset{|}{\mathop{CH}}}}-CH_3}}+\underset{\begin{smallmatrix} Ethoxymagnesium \\ bromide \end{smallmatrix}}{\mathop{C_2H_5OMgBr}} $
BETA
