Hydrocarbons Question 43
Question: In the reaction, $ H_2C=CH_2\xrightarrow{\begin{smallmatrix} \text{cold alkaline} \\ KMn{O_4} \end{smallmatrix}}(A) $ : Product A is : [Pb. CET 2000]
Options:
A) Ethylene glycol
B) Acetic acid
C) Ethane
D) Butyric acid
Show Answer
Answer:
Correct Answer: A
Solution:
When ethylene is treated with cold alkaline $ KMnO4 $ , ethylene glycol is formed.
$ \begin{matrix} H \\ H \\ \end{matrix}>C=C<\begin{matrix} H \\ H \\ \end{matrix}\underset{\text{Cold alkaline}}{\mathop{\xrightarrow{KMnO4}}}\underset{\text{Ethylene glycol}}{\mathop{\begin{matrix} H \\ H \\ \end{matrix}>\underset{OH}{\mathop{\ \underset{|}{\mathop{C}}-}}\underset{OH}{\mathop{\underset{|}{\mathop{C}}\ \ }}<\begin{matrix} H \\ H \\ \end{matrix}}} $
BETA
