Hydrocarbons Question 66
Question: $ R-CH_2-CCl_2-R\xrightarrow{Reagent}R-C\equiv C-R $ The reagent is [CBSE PMT 1989; MP PET 1995]
Options:
A) Na
B) $ HCl\text{ and }H_2O $
C) $ KOH\text{ in }C_2H_5OH $
D) Zn
Show Answer
Answer:
Correct Answer: C
Solution:
$ R-CH_2-CCl_2-R\xrightarrow{KOH+C_2H_5OH} $
$ R-C\equiv C-R+2HCl $
This reaction is an example of dehydrohalogenation Hence, alcoholic $ KOH $ is used as a reagent.
BETA
