Hydrocarbons Question 71
Question: $ CH\equiv CH\underset{H_2SO_4}{\mathop{\xrightarrow{H_2O/H{g^{2+}}}}}X\xrightarrow{LiAlH_4}Y\xrightarrow{P_4/Br_2}Z $ Here Z is [JIPMER 2002]
Options:
A) Ethylene bromide
B) Ethanol
C) Ethyl bromide
D) Ethylidene bromide
Show Answer
Answer:
Correct Answer: C
Solution:
$ CH\equiv CH\underset{H_2SO_4}{\mathop{\xrightarrow{H_2O/H{g^{2+}}}}}H_3C-\underset{(\times )}{\overset{\overset{O}{\mathop{||}}}{\mathop{C}}}-H $
$ CH_3-\underset{(y)}{\mathop{CH_2}}-OH\xrightarrow{{P_4}\text{/}Br_2}\underset{(z)}{\mathop{C_2H_5Br}} $
BETA
