Hydrocarbons Question 8
Question: If HCl is added over $ CH_2=C<\begin{matrix} CH_3 \\ CH_3 \\ \end{matrix} $ then what is formed [CPMT 1996]
Options:
A) $ \underset{Cl}{\mathop{\underset{|}{\mathop{CH_2}}}}=C<\begin{matrix} CH_3 \\ CH_3 \\ \end{matrix} $
B) $ \underset{}{\mathop{\underset{}{\mathop{CH_2}}}}-CH<-\begin{matrix} Cl \\ CH_3 \\ CH_3 \\ \end{matrix} $
C) $ $ $ \underset{}{\mathop{\underset{}{\mathop{CH_2}}}}=C<\begin{matrix} CH_3 \\ CH_2Cl \\ \end{matrix} $
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
$ CH_2=\underset{CH_3}{\mathop{\underset{|}{\mathop{C-}}C}}H_3+\overset{}{\mathop{HCl}}\to \underset{\begin{smallmatrix} \text{2-chloro-2-methyl} \\ propane \end{smallmatrix}}{\mathop{CH_3-\underset{CH_3}{\overset{Cl}{\mathop{\underset{|}{\overset{|}{\mathop{C-}}}}}}CH_3}} $
BETA
