Hydrocarbons Question 88
Question: When treated with ammoniacal cuprous chloride, which one among the following forms copper derivative [CBSE PMT 1989; MP PMT 1993]
Options:
A) $ C_2H_6 $
B) $ C_2H_4 $
C) $ C_2H_2 $
D) $ C_6H_6 $
Show Answer
Answer:
Correct Answer: C
Solution:
$ 2NH_4OH+Cu_2Cl_2\to 2CuOH+2NH_4Cl $
$ NH_4OH+CuOH\to \underset{\begin{smallmatrix} \text{Diammine copper} \\ ( I )\text{ hydroxide} \end{smallmatrix}}{\mathop{[Cu{{(NH_3)}_2}]OH}} $
$ 2[Cu{{(NH_3)}_2}]OH+HC\equiv CH\to $
$ \underset{\text{copper acetylide Red ppt}\text{.}}{\mathop{Cu-C\equiv C-Cu}}+4NH_3+2H_2O $
BETA
