Hydrocarbons Question 90
Question: $ \begin{matrix} H_3C & {} & CH_3 \\ {} & >C=C< & {} \\ H_3C & {} & CH_3 \\ \end{matrix}\underset{KOH\text{(heat)}}{\mathop{\xrightarrow{X}}}\begin{matrix} CH_3 & {} & CH_3 \\ {} & >C=O+O=C< & {} \\ CH_3 & {} & CH_3 \\ \end{matrix} $ $ X $ in the above reaction is [CPMT 1985, 93]
Options:
A) $ HNO_3 $
B) $ O_2 $
C) $ O_3 $
D) $ KMnO_4 $
Show Answer
Answer:
Correct Answer: D
Solution:
$ \begin{matrix} CH_3 \\ CH_3 \\ \end{matrix}>C=C<\begin{matrix} CH_3 \\ CH_3 \\ \end{matrix}\underset{KOH(\text{heat)}}{\mathop{\xrightarrow{KMnO_4}}} $
$ \begin{matrix} CH_3 \\ \underset{Acetone}{\mathop{CH_3}} \\ \end{matrix}>C=O+O=C<\begin{matrix} CH_3 \\ \underset{Acetone}{\mathop{CH_3}} \\ \end{matrix} $
BETA
