Hydrogen And Its Compounds Question 126
Question: $ H_2O_2\to 2{H^{+}}+O_2+2{e^{-}} $ ; $ E{}^\circ =-0.68V $ . This equation represents which of the following behaviour of $ H_2O_2 $
Options:
A) Reducing
B) Oxidising
C) Acidic
D) Catalytic
Show Answer
Answer:
Correct Answer: A
Solution:
As $ H_2O_2 $ is loosing electrons so it is acting as reducing agent.
BETA
