Hydrogen And Its Compounds Question 234
Question: 34 g of $ H_2O_2 $ is present in 1120 mL of solution. This solution is called
Options:
A) 10 vol solution
B) 20 vol solution
C) 34 vol solution
D) 32 vol solution
Show Answer
Answer:
Correct Answer: A
Solution:
[a] $ N=\frac{W_2\times 1000}{E.W_2\times VmL} $
$ =\frac{34\times 1000}{17\times 1120}=\frac{200}{12} $ 1 N of $ H_2O_2=5.6 $ vol strength $ \frac{200}{12}NofH_2O_2=5.6\times \frac{200}{12}=10 $ vol strength
BETA
