Hydrogen And Its Compounds Question 241
Question: $ H_2O_2\to 2{H^{+}}+O_2+2{e^{-}};E{}^\circ =-0.68V. $ This equation represents which of the following behaviour of $ H_2O_2 $ -
Options:
A) Reducing
B) Oxidising
C) Acidic
D) Catalytic
Show Answer
Answer:
Correct Answer: A
Solution:
[a] As $ H_2O_2 $ is loosing electrons, so it is acting as reducing agent.
BETA
