Nuclear Chemistry Question 14
Question: The half-life period of $ Pb^{210} $ is 22 years. If 2 gm of $ Pb^{210} $ is taken, then after 11 years how much of $ Pb^{210} $ will be left
[KCET 2001]
Options:
A) 1.414 gm
B) 2.428 gm
C) 3.442 gm
D) 4.456 gm
Show Answer
Answer:
Correct Answer: A
Solution:
$ N _{t}=N _{o}{{( \frac{1}{2} )}^{2}} $ [
$ \therefore {t _{1/2}} $ = 22 years, T = 11 years, $ N _{o} $ =2, $ N _{t} $ =-] $ T={t _{1/2}}\times n, $ 11= 2 × n or $ n=\frac{11}{22}=\frac{1}{2} $
$ \therefore N _{t}=2gm\times {{( \frac{1}{2} )}^{1/2}}=1.414gm $ .
BETA
