Nuclear Chemistry Question 15
Question: A wood specimen from an archeological centre shows a $ _6^{14}C $ activity of 5.0 counts/min/gm of carbon. What is the age of the specimen $ ({t _{1/2}} $ for $ _6^{14}C $ is 5000 years) and a freshly cut wood gives 15 counts/min/gm of carbon
[AMU (Engg.) 2002]
Options:
A) $ 5.78\times 10^{4} $ years
B) $ 9.85\times 10^{4} $ years
C) $ 7.85\times 10^{3} $ years
D) $ 0.85\times 10^{4} $ years
Show Answer
Answer:
Correct Answer: C
Solution:
$ t=\frac{2.303}{0.693}\times 5000\times \log \frac{15}{5} $
$ =\frac{2.303}{0.693}\times 5000\times \log 3=7927=7.92\times 10^{3}yrs\text{.} $
BETA
