Nuclear Chemistry Question 17
Question: $ _{92}U^{235}+n\to $ fission product+neutron $ +3.20\times {{10}^{-11}}J $ . The energy released when $ 1g $ of $ _{92}U^{235} $ undergoes fission is
[CBSE PMT 1997]
Options:
A) $ 12.75\times 10^{8}kJ $
B) $ 18.60\times 10^{9}kJ $
C) $ 8.21\times 10^{7}kJ $
D) $ 6.55\times 10^{6}kJ $
Show Answer
Answer:
Correct Answer: C
Solution:
1g U-235 $ =\frac{6.023\times 10^{23}}{235}\ atoms $
$ \therefore $ energy released $ =3.2\times {{10}^{-11}}\times \frac{6.023\times 10^{23}}{235}J=8.21\times 10^{10}J $
$ =8.2\times 10^{7}kJ $ .
BETA
