Nuclear Chemistry Question 20
Sulphur-35 (34.96903 amu) emits a $ \beta - $ particle but no $ \gamma - $ rays, the product is chlorine-35 (34.96885 amu). The maximum energy emitted by the $ \beta - $ particle is 0.00018 amu
[DPMT 2004]
Options:
A) 0.016767 MeV
B) 1.6758 MeV
C) 0.16758 MeV
D) 16.758 MeV
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Answer:
Correct Answer: A
Solution:
Mass defect = mass of sulphur - mass of chlorine $ =34.96903-35.45380 $
$ =0.00018\text{ g} $ Binding energy =mass defect $ \times $ 931 $ =0.00018\times 931 $
$ =0.1675MeV $