Nuclear Chemistry Question 25
Question: A radioactive nucleide X decays at the rate of $ 1.00\times 10^{5} $ disintegration $ {{s}^{-1}}{{g}^{-1}} $ . Radium decays at the rate of $ 3.70\times 10^{10} $ disintegration $ {{s}^{-1}}{{g}^{-1}} $ . The activity of X in millicuries $ {{g}^{-1}} $ $ (mci{{g}^{-1}}) $ is
[MP PET 2001]
Options:
A) 0.027
B) $ 0.270\times {{10}^{-5}} $
C) 0.00270
D) 0.000270
Show Answer
Answer:
Correct Answer: B
Solution:
$ \frac{dx_1}{dt}=\lambda N_1,1\times 10^{5}=\lambda N_1 $
$ \frac{dx_2}{dt}=\lambda N_2,3.7\times 10^{10}=\lambda N_2 $
$ \frac{N_1}{N_2}=\frac{1\times 10^{5}}{3.7\times 10^{10}}=\frac{1\times {{10}^{-5}}}{3.7}=0.27\times {{10}^{-5}} $ .
BETA
