Nuclear Chemistry Question 26
Question: If $ _{92}U^{235} $ nucleus absorbs a neutron and disintegrates in $ _{54}Xe^{139} $ , $ _{38}Sr^{94} $ and X, then what will be the product X
[CBSE 2002]
Options:
A) a-particle
B) b-particle
C) 2-neutrons
D) 3-neutrons
Show Answer
Answer:
Correct Answer: D
Solution:
$ _{92}U^{235}+ _on^{1} \to _{54}X _{e}^{139}+ _{38}Sr^{94}+3 _on^{1} $
BETA
