Organic Compounds Containing Halogens Question 17
Question: In $ CH_3CH_2Br,% $ of Br is
[DPMT 1996]
Options:
A) 80
B) 75
C) 70
D) 7
Show Answer
Answer:
Correct Answer: B
Solution:
% of Br $ =\frac{MassofBr}{\text{Mass of organic compound}}\times 100 $
$ =\frac{80}{109}\times 100=73.39% $ or approx. 75%