Organic Compounds Containing Halogens Question 17

Question: In $ CH_3CH_2Br,% $ of Br is

[DPMT 1996]

Options:

A) 80

B) 75

C) 70

D) 7

Show Answer

Answer:

Correct Answer: B

Solution:

% of Br $ =\frac{MassofBr}{\text{Mass of organic compound}}\times 100 $

$ =\frac{80}{109}\times 100=73.39% $ or approx. 75%