Organic Compounds Containing Halogens Question 77
Question: Treatment of ammonia with excess of ethyl chloride will yield
[AIIMS 1992]
Options:
A) Diethyl amine
B) Ethane
C) Tetraethyl ammonium chloride
D) Methyl amine
Show Answer
Answer:
Correct Answer: C
Solution:
$ C_2H_5Cl\xrightarrow{NH_3}C_2H_5-NH_2\xrightarrow{C_2H_5Cl}{{(C_2H_5)}_2}-NH \xrightarrow{C_2H_5Cl}{{(C_2H_5)}_3}N\xrightarrow{C_2H_5Cl}\underset{Tetraethylammoniumchloride}{\mathop{{{[ C_2H_5-\underset{\underset{C_2H_5}{\mathop{|}}}{\mathop{\overset{\overset{C_2H_5}{\mathop{|}}}{\mathop{N-C_2H_5}}}} ]}^{+}}C{l^{-}}}} $
If $ NH_3 $ is in excess, then $ 1^{o} $ amine will be the main product, if $ C_2H_5Cl $ is in excess then mixture of $ 1^{o},2^{o},3^{o} $ and quaternary amine is obtained.
BETA
