[CPMT 1993]
A) $ Na_2SO_4 $
B) $ BiOCl $
C) $ Pb(OH)Cl $
D) $ Na_2HPO_4 $
Correct Answer: D
$ Na_2HPO_4\to Na_2PO_4^{-}+{{H}^{+}} $ It can give $ {{H}^{+}} $ ion in solution.
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