A) By donating $ H^{+} $
B) By accepting $ OH^{-} $
C) By donating a lone pair of electrons
D) By accepting a lone pair of electrons.
Correct Answer: B
$ B{{(OH)}_3}+2H_2O\rightarrow {{[B{{(OH)}_4}]}^{-}}+H_3{{O}^{+}} $
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