P Block Elements Question 399
Question: Ge(II)compounds are powerful reducing agents whereas Pb(IV)compounds are strong oxidants. It is because
Options:
A) Pb is more electropositive than Ge
B) ionization potential of lead is less than that of Ge
C) ionic radii of $ P{{b}^{2+}} $ and $ P{{b}^{4+}} $ are larger than those of $ G{{e}^{2+}} $ and $ G{{e}^{4+}} $
D) of more pronounced inert pair effect in lead than in Ge
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Answer:
Correct Answer: D
Solution:
Ge(II) tends to acquire Ge (IV) state by loss of electrons. Hence it is reducing in nature. Pb (IV) tends to acquire Pb (II) O.S. by gain of electrons. Hence it is oxidising in nature. This is due to inert pair effect.
BETA
