P Block Elements Question 453

Question: Anhydrous $ AlCl_3 $ is prepared from

Options:

A) cone. $ HCl $ and Al metal reaction

B) aluminium and $ Cl_2 $

C) dry $ HCl $ gas + heated Al metal

D) dil. $ HCl $ and Al metal

Show Answer

Answer:

Correct Answer: C

Solution:

$ 2Al+3Cl_2\xrightarrow{\Delta }2AlCl_3 $ (anhydrous)



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