P Block Elements Question 536
Question: The reaction of $ KMnO_4 $ and $ HCl $ results in
Options:
A) oxidation of Mn in $ KMnO_4 $ and production of $ Cl_2 $ .
B) reduction of Mn in $ KMnO_4 $ and production of $ H_2 $ .
C) oxidation of Mn in $ KMnO_4 $ and production of $ H_2 $ .
D) reduction of Mn in $ KMnO_4 $ and production of $ Cl_2 $ .
Show Answer
Answer:
Correct Answer: D
Solution:
$ 2\overset{+1}{\mathop{KM}}nO_4+16HCl\to 2\overset{+2}{\mathop{Mn}}Cl_2+2KCl $ $ +8H_2O+5Cl_2 $ O.S of Mn changes from +7 to +2 hence reduction occurs and $ Cl_2 $ is formed.
BETA
