P Block Elements Question 538
Question: One mole of fluorine is reacted with two moles of hot and concentrated $ KOH $ . The products formed are $ KF,H_2O $ and $ O_2 $ . The molar ratio of $ KF,H_2O $ and $ O_2 $ respectively is
Options:
A) 1:1:2
B) 2:1:0.5
C) 1:2:1
D) 2:1:2
Show Answer
Answer:
Correct Answer: B
Solution:
$ 2F_2+4KOH\to 4KF+O_2+2H_2O $ for 1 mole of $ F_2 $ the molar ratio. $ \begin{matrix} F_2 & KOH & KF & O_2 & H_2O \\ 1 & 2 & 2 & \frac{1}{2} & 1 \\ \end{matrix} $
BETA
