A) $ CH\equiv CH $
B) $ CH_2=CH_2 $
C) $ CH_3-CH=CH_2 $
D) $ CH_3-C\equiv CH $
Correct Answer: C
$ \underset{Propene}{\mathop{nCH_3}}CH=CH_2\to \underset{Polypropylene}{\mathop{{{(-CH_2-\underset{CH_3}{\mathop{\underset{|}{\mathop{CH-}}}})} _{n}}}} $
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