A) $ CH_2=CH-CH_2-Cl $
B) $ CH_2=CH-Cl $
C) $ CH_3-Cl $
D) $ CH_3-CHCl_2 $
Correct Answer: B
$ \underset{\text{Vinyl chloride}}{\mathop{n(CH_2=CH-Cl}})\to \underset{(PVC)}{\mathop{{{(-CH_2-\underset{Cl}{\mathop{\underset{|}{\mathop{CH}}}}-)} _{n}}}} $
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