Polymers Question 50
Formation of polyethylene from calcium carbide takes place as follows: $ CaC_2+2H_2O\to Ca{(OH)}_2+C_2H_2 $ $ C_2H_2+H_2\to C_2H_4 $ $ nC_2H_4\to {(-CH_2-CH_2-)}_n $ The amount of polyethylene obtained from 64.1 kg of $ CaC_2 $ is
Options:
A) 7 kg
B) 4 kg
C) 21 kg
D) 28 kg
Show Answer
Answer:
Correct Answer: B
Solution:
[d] $ CaC_2(64kg) $ will produce 28 kg of $ {{(-CH_2-CH_2-)} _{n}} $ .
BETA
