Purification And Characterisation Of Organic Compounds Question 145
Question: When $ CuSO_4 $ is electrolysed using platinum electrodes,
Options:
A) copper is liberated at cathode, sulphur at anode
B) copper is liberated at cathode, oxygen at anode
C) sulphur is liberated at cathode; oxygen anode
D) oxygen is liberated at cathode, copper at anode
Show Answer
Answer:
Correct Answer: B
Solution:
[b] $ CuSO_4\rightarrow C{{u}^{2+}}+SO_4^{2-} $
$ H_2O\rightarrow {{H}^{+}}+O{{H}^{-}} $ At cathode: $ C{{u}^{2+}}+2{{e}^{-}}\to Cu $ At anode: $ 4O{{H}^{-}}\to 2H_2O+O_2+4{{e}^{-}}~ $
BETA
