Purification And Characterisation Of Organic Compounds Question 183
Question: $ XCl_2(excess)+YCl_2\xrightarrow{{}}XCl_4+Y\downarrow ; $ $ YO\xrightarrow[>400{}^\circ ]{\Delta }\frac{1}{2}O_2+Y, $ Ore of Y would be:
Options:
A) Siderite
B) Cinnabar
C) Malachite
D) Hornsilver
Show Answer
Answer:
Correct Answer: B
Solution:
[b] $ \underset{( XCl_2 )}{\mathop{SnCl_2}}+\underset{( YCl_2 )}{\mathop{HgCl_2}}\xrightarrow{{}}\underset{( XCl_4 )}{\mathop{SnCl_4}}+\underset{(Y)}{\mathop{Hg}} $
$ HgO+\xrightarrow[>400{}^\circ C]{\Delta }Hg+\frac{1}{2}O_2 $ HgS: Cinnabar
BETA
