Redox Reaction Subtopic Half Reaction Method 01 Ques7
Question: In the half-reaction $Cr_2O_7^{2-} + 14H^+ + 6e^- \rightarrow 2Cr^{3+} + 7H_2O $ what is the role of $Cr_2O_7^{2-}$ ?
Options:
A) Reducing agent
B) Oxidizing agent
C) Catalyst
D) Spectator ion
Show Answer
Answer: b
Explanation:
A) $Cr_2O_7^{2-}$ is being reduced, not oxidized.
B) Correct. $Cr_2O_7^{2-}$ is the oxidizing agent as it accepts electrons and is reduced.
C) It’s a reactant, not a catalyst.
D) It’s actively participating in the reaction, not a spectator.
BETA
