Redox Reactions And Electrochemistry Question 137
Question: The number of electrons passing per second through a cross-section of copper wire carrying $ {10^{-6}} $ amperes of current per second is found to be [EAMCET 1985]
Options:
A) $ 1.6\times {10^{-19}} $
B) $ 6\times {10^{-35}} $
C) $ 6\times {10^{-16}} $
D) $ 6\times 10^{12} $
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Answer:
Correct Answer: D
Solution:
Charge (Coulombs) pass per second $ ={10^{-6}} $ number of electrons passed per second $ =\frac{{10^{-6}}}{1.602\times {10^{-19}}}=6.24\times 10^{12} $ .
BETA
