Redox Reactions And Electrochemistry Question 144
Question: A current of strength 2.5 amp was passed through $ CuSO_4 $ solution for 6 minutes 26 seconds. The amount of copper deposited is (Atomic weight of $ Cu=63.5 $ ) (1 faraday = 96500 coulombs) [EAMCET 1989; MP PET 1994]
Options:
A) 0.3175 g
B) 3.175 g
C) 0.635 g
D) 6.35 g
Show Answer
Answer:
Correct Answer: A
Solution:
$ Q=2.5\times 386=96500,C $
$ 2F(2\times 96500C) $ deposited $ Cu=63.5,g $
Hence 965 C will be deposited; $ Cu=0.3175, \text{g} $ .
BETA
