Redox Reactions And Electrochemistry Question 185
Question: Electrode potential data are given below. $ F{e^{3+}}~( aq )\text{+}{e^{-}}\to F{e^{2+}}( aq ); $ $ E{}^\circ =+,0.77 $ $ A{l^{3+}}( aq )\text{+3}{e^{-}}\to \text{Al(s);} $ $ E{}^\circ =-,1.66V $ $ Br_2(aq)+2{e^{-}}\to 2B{r^{-}}(aq); $ $ E{}^\circ =+,1.08V $ Based on the data given above, reducing power of $ F{e^{2+}} $ , Al and $ B{r^{-}} $ will increase in the order
Options:
A) $ B{r^{-}}<F{e^{2+}}<Al $
B) $ F{e^{2+}}<Al<B{r^{-}} $
C) $ Al<B{r^{-}}<F{e^{2+}} $
D) $ Al<F{e^{2+}}<B{r^{-}} $
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Answer:
Correct Answer: A
Solution:
[a] The lowest the standard reduction potential, the highest is the reducing power.
BETA
